Optimal. Leaf size=165 \[ \frac{\tan ^3(c+d x) (4 a A+5 a C+5 b B)}{15 d}+\frac{\tan (c+d x) (4 a A+5 a C+5 b B)}{5 d}+\frac{(3 a B+3 A b+4 b C) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{\tan (c+d x) \sec (c+d x) (3 a B+3 A b+4 b C)}{8 d}+\frac{(a B+A b) \tan (c+d x) \sec ^3(c+d x)}{4 d}+\frac{a A \tan (c+d x) \sec ^4(c+d x)}{5 d} \]
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Rubi [A] time = 0.255276, antiderivative size = 165, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 6, integrand size = 39, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154, Rules used = {3031, 3021, 2748, 3767, 3768, 3770} \[ \frac{\tan ^3(c+d x) (4 a A+5 a C+5 b B)}{15 d}+\frac{\tan (c+d x) (4 a A+5 a C+5 b B)}{5 d}+\frac{(3 a B+3 A b+4 b C) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{\tan (c+d x) \sec (c+d x) (3 a B+3 A b+4 b C)}{8 d}+\frac{(a B+A b) \tan (c+d x) \sec ^3(c+d x)}{4 d}+\frac{a A \tan (c+d x) \sec ^4(c+d x)}{5 d} \]
Antiderivative was successfully verified.
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Rule 3031
Rule 3021
Rule 2748
Rule 3767
Rule 3768
Rule 3770
Rubi steps
\begin{align*} \int (a+b \cos (c+d x)) \left (A+B \cos (c+d x)+C \cos ^2(c+d x)\right ) \sec ^6(c+d x) \, dx &=\frac{a A \sec ^4(c+d x) \tan (c+d x)}{5 d}-\frac{1}{5} \int \left (-5 (A b+a B)-(4 a A+5 b B+5 a C) \cos (c+d x)-5 b C \cos ^2(c+d x)\right ) \sec ^5(c+d x) \, dx\\ &=\frac{(A b+a B) \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{a A \sec ^4(c+d x) \tan (c+d x)}{5 d}-\frac{1}{20} \int (-4 (4 a A+5 b B+5 a C)-5 (3 A b+3 a B+4 b C) \cos (c+d x)) \sec ^4(c+d x) \, dx\\ &=\frac{(A b+a B) \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{a A \sec ^4(c+d x) \tan (c+d x)}{5 d}-\frac{1}{5} (-4 a A-5 b B-5 a C) \int \sec ^4(c+d x) \, dx-\frac{1}{4} (-3 A b-3 a B-4 b C) \int \sec ^3(c+d x) \, dx\\ &=\frac{(3 A b+3 a B+4 b C) \sec (c+d x) \tan (c+d x)}{8 d}+\frac{(A b+a B) \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{a A \sec ^4(c+d x) \tan (c+d x)}{5 d}-\frac{1}{8} (-3 A b-3 a B-4 b C) \int \sec (c+d x) \, dx-\frac{(4 a A+5 b B+5 a C) \operatorname{Subst}\left (\int \left (1+x^2\right ) \, dx,x,-\tan (c+d x)\right )}{5 d}\\ &=\frac{(3 A b+3 a B+4 b C) \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{(4 a A+5 b B+5 a C) \tan (c+d x)}{5 d}+\frac{(3 A b+3 a B+4 b C) \sec (c+d x) \tan (c+d x)}{8 d}+\frac{(A b+a B) \sec ^3(c+d x) \tan (c+d x)}{4 d}+\frac{a A \sec ^4(c+d x) \tan (c+d x)}{5 d}+\frac{(4 a A+5 b B+5 a C) \tan ^3(c+d x)}{15 d}\\ \end{align*}
Mathematica [A] time = 1.28905, size = 123, normalized size = 0.75 \[ \frac{15 (3 a B+3 A b+4 b C) \tanh ^{-1}(\sin (c+d x))+\tan (c+d x) \left (8 \left (5 \tan ^2(c+d x) (a (2 A+C)+b B)+15 (a (A+C)+b B)+3 a A \tan ^4(c+d x)\right )+15 \sec (c+d x) (3 a B+3 A b+4 b C)+30 (a B+A b) \sec ^3(c+d x)\right )}{120 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.062, size = 287, normalized size = 1.7 \begin{align*}{\frac{Ab \left ( \sec \left ( dx+c \right ) \right ) ^{3}\tan \left ( dx+c \right ) }{4\,d}}+{\frac{3\,Ab\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{8\,d}}+{\frac{3\,Ab\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}}+{\frac{2\,bB\tan \left ( dx+c \right ) }{3\,d}}+{\frac{bB\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{3\,d}}+{\frac{Cb\tan \left ( dx+c \right ) \sec \left ( dx+c \right ) }{2\,d}}+{\frac{Cb\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{2\,d}}+{\frac{8\,A\tan \left ( dx+c \right ) a}{15\,d}}+{\frac{aA \left ( \sec \left ( dx+c \right ) \right ) ^{4}\tan \left ( dx+c \right ) }{5\,d}}+{\frac{4\,aA \left ( \sec \left ( dx+c \right ) \right ) ^{2}\tan \left ( dx+c \right ) }{15\,d}}+{\frac{Ba \left ( \sec \left ( dx+c \right ) \right ) ^{3}\tan \left ( dx+c \right ) }{4\,d}}+{\frac{3\,Ba\sec \left ( dx+c \right ) \tan \left ( dx+c \right ) }{8\,d}}+{\frac{3\,Ba\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}}+{\frac{2\,aC\tan \left ( dx+c \right ) }{3\,d}}+{\frac{aC\tan \left ( dx+c \right ) \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{3\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.03263, size = 359, normalized size = 2.18 \begin{align*} \frac{16 \,{\left (3 \, \tan \left (d x + c\right )^{5} + 10 \, \tan \left (d x + c\right )^{3} + 15 \, \tan \left (d x + c\right )\right )} A a + 80 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} C a + 80 \,{\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} B b - 15 \, B a{\left (\frac{2 \,{\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 15 \, A b{\left (\frac{2 \,{\left (3 \, \sin \left (d x + c\right )^{3} - 5 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} - 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 60 \, C b{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )}}{240 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.77455, size = 467, normalized size = 2.83 \begin{align*} \frac{15 \,{\left (3 \, B a +{\left (3 \, A + 4 \, C\right )} b\right )} \cos \left (d x + c\right )^{5} \log \left (\sin \left (d x + c\right ) + 1\right ) - 15 \,{\left (3 \, B a +{\left (3 \, A + 4 \, C\right )} b\right )} \cos \left (d x + c\right )^{5} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \,{\left (16 \,{\left ({\left (4 \, A + 5 \, C\right )} a + 5 \, B b\right )} \cos \left (d x + c\right )^{4} + 15 \,{\left (3 \, B a +{\left (3 \, A + 4 \, C\right )} b\right )} \cos \left (d x + c\right )^{3} + 8 \,{\left ({\left (4 \, A + 5 \, C\right )} a + 5 \, B b\right )} \cos \left (d x + c\right )^{2} + 24 \, A a + 30 \,{\left (B a + A b\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{240 \, d \cos \left (d x + c\right )^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.20227, size = 639, normalized size = 3.87 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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